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华邦新华城一期6#地块施工升降机基础施工方案???????:
6.3 、21#工字钢加固施工升降机计算书
1?«??????????????»?????
DB34／T 1981-2013标准下载 1.?????????
????(??80????,????167kg):167kg×80=13360kg,
??????????:Pk=((1460×2+1480+1300×2+200+13360)+2000×2)×10/1000=245.6kN;
???????:P=(1.2×(1460×2+1480+1300×2+200+13360)+1.4×2000×2)×10/1000=302.72kN;
P=n×P=2.5×302.72=756.8kN
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????14???????????????,??????????????,?:
????:N=P +1.4×q×a×b =756.8+1.4×8×5.4×3.4=962.432kN
?lo=1.0×h0=1.0×3720=3720mm
λ=l0/i=3720/57.6=64.583?[λ]=200
[f]=N/(φ×A)=962432/(0.802×6450)= 186.053N/mm2=[f]=205N/mm2
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6.4 、 22#工字钢加固施工升降机计算书
1?«??????????????»?????
1.?????????
????(??80????,????167kg):167kg×80=13360kg,
??????????:Pk=((1460×2+1480+1300×2+200+13360)+2000×2)×10/1000=245.6kN;
???????:P=(1.2×(1460×2+1480+1300×2+200+13360)+1.4×2000×2)×10/1000=302.72kN;
P=n×P=2.5×302.72=756.8kN
?????????????
????14???????????????,??????????????,?:
????:N=P +1.4×q×a×b =756.8+1.4×8×5.4×3.4=962.432kN
?lo=1.0×h0=1.0×3720=3720mm
λ=l0/i=3720/57.6=64.583?[λ]=200
[f]=N/(φ×A)=962432/(0.802×6450)= 186.053N/mm2=[f]=205N/mm2
??????????????!
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6.5、23#工字钢加固施工升降机计算书
1?«??????????????»?????
1.?????????
????(??80????,????167kg):167kg×80=13360kg,
??????????:Pk=((1460×2+1480+1300×2+200+13360)+2000×2)×10/1000=245.6kN;
???????:P=(1.2×(1460×2+1480+1300×2+200+13360)+1.4×2000×2)×10/1000=302.72kN;
P=n×P=2.5×302.72=756.8kN
?????????????
????14???????????????,??????????????,?:
????:N=P +1.4×q×a×b =756.8+1.4×8×5.4×3.4=962.432kN
?lo=1.0×h0=1.0×3720=3720mm
λ=l0/i=3720/230.4=16.146?[λ]=200
[f]=N/(φ×A)=962432/(0.983×6450)= 151.795N/mm2=[f]=205N/mm2
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6.6、24#工字钢加固施工升降机计算书
1?«??????????????»?????
1.?????????
????(??80????,????167kg):167kg×80=13360kg,
??????????:Pk=((1460×2+1480+1300×2+200+13360)+2000×2)×10/1000=245.6kN;
???????:P=(1.2×(1460×2+1480+1300×2+200+13360)+1.4×2000×2)×10/1000=302.72kN;
P=n×P=2.5×302.72=756.8kN
?????????????
????14???????????????,??????????????,?:
????:N=P +1.4×q×a×b =756.8+1.4×8×5.4×3.4=962.432kN
?lo=1.0×h0=1.0×3720=3720mm
λ=l0/i=3720/57.6=64.583?[λ]=200
[f]=N/(φ×A)=962432/(0.802×6450)= 186.053N/mm2=[f]=205N/mm2
??????????????!
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6.7 25#楼施工升降机计算书
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1?«??????????????»?????
1.?????????
????(??80????,????197kg):197kg×80=15760kg,
??????????:Pk=((1750×2+1608+2700×2+200+15760)+4000×2)×10/1000=344.68kN;
???????:P=(1.2×(1750×2+1608+2700×2+200+15760)+1.4×4000×2)×10/1000=429.616kN;
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Pj=1.2×l×d×h×25=1.2×4×4×0.4×25=192KN
P=n×(P+ Pj)=1.4×(429.616+192)=870.262kN
???????:Gk=25×6.50×3.70×0.50=300.63kN
???????: G=300.63×1.2=360.75kN
?????????????:F=902.19+360.75=1262.94kN
?????????:fa= 160.00×6.50×3.70×0.40=1539.20kN > F=1262.94kN
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1????????
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S=6.5×3.7=24.05m2=(Pk+Gk)/fc=(344.68+300.625)/(14.3×103)=0.045m2?
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2????????
????????????,????????????????
??????:
F1 ? 0.7βhpftamho am = (at+ab)/2 F1 = pj×Al
ab=a+2h0=0.45+2×0.465=1.38m
am=(at+ab)/2=(0.45+1.38)/2=0.915m
Fl=Pj×Al=37.513×9.342=350.468kN
0.7βhpftamh0=0.7×1×1.43×915×465/1000=425.9kN=350.468kN?
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3?????????
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4?????????
αs = M/(α1fcbh02)
As = M/(γsh0fy)
As=|M|/(γsfyh0)=426.66×106/(0.981×360.00×465.00)=2598.15mm2?
As=|M|/(γsfyh0)=210.96×106/(0.995×360.00×465.00)=1266.88mm2?
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6.8、26满堂架加固施工升降机计算书
1?«??????????????»?????
1.?????????
????(??80????,????167kg):167kg×80=13360kg,
??????????:Pk=((1460×2+1480+1300×2+200+13360)+2000×2)×10/1000=245.6kN;
???????:P=(1.2×(1460×2+1480+1300×2+200+13360)+1.4×2000×2)×10/1000=302.72kN;
P=n×P=2.5×302.72=756.8kN
???????????
??????:q=P/(a ×c )=756.8/(3.5×5.4)=40.042kN/m2
a:???????
c:???????
N=(NGK+1.4×NQK)×la×lb=(40.042+1.4×8)×0.5×0.4=10.248kN
1??????????
DG／TJ08-2280-2018标准下载 ?N?=30 =N=10.248kN
2????????
?????:λ=l0/i=kμ1(h+2a)/i= 1×2.5×(0.9+2×0.2)/0.0159 =204.403 =[λ]=210
??????:λ=l0/i=kμ2h/i= 1×2.1×1.5/0.0159 =198.113 =[λ]=210
?????:λ1=l0/i=kμ1(h+2a)/i= 1.155×2.5×(0.9+2×0.2)/0.0159 =236.085
??????:λ2=l0/i=kμ2h/i= 1.155×2.1×1.5/0.0159 =228.821
f= N/(φA)= 10248/(0.131×424)=184.502N/mm2= [f]=205N/mm2
T／CSA 004-2010 半导体照明试点示范工程LED道路和隧道照明现场检测及验收实施细则 ????????????!
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