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太湖大道南侧B3地块普通模板专项施工方案.doc

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??????????,b=1000mm?W=bh2/6=1000×152/6=37500mm3,I=bh3/12=1000×153/12=281250mm4???????:

JGT194-2018 住宅厨房和卫生间排烟(气)道制品 q1=bS?=1×37.02=37.02kN/m

Mmax=0.125q1l2=0.125×37.02×0.22=0.185kN·m

σ=Mmax/W=0.185×106/37500=4.936N/mm2=[f]=15N/mm2

q=bS?=1×26.4=26.4kN/m

νmax=5×26.4×2004/(384×5400×281250)=0.362mm=200/400=0.5mm

3???????

????????

R??=q1l=37.02×0.2=7.404kN

????????

R'??=ql=26.4×0.2=5.28kN

??????????,b=1000mm?W=bh2/6=1000×152/6=37500mm3,I=bh3/12=1000×153/12=281250mm4???????:

q1=bS?=1×32.652=32.652kN/m

Mmax=0.125q1l2=0.125×32.652×0.22=0.163kN·m

σ=Mmax/W=0.163×106/37500=4.354N/mm2=[f]=15N/mm2

q=bS?=1×23.04=23.04kN/m

νmax=5×23.04×2004/(384×5400×281250)=0.316mm=200/400=0.5mm

3???????

????????

R???=q1l=32.652×0.2=6.53kN

????????

R'???=ql=23.04×0.2=4.608kN

??????:

?????(kN·m)

q=7.404kN/m

σ=Mmax/W=0.148×106/54000=2.742N/mm2=[f]=15.444N/mm2

?????(kN)

τmax=3 Vmax/(2bh)=3×1.49×1000/(2×90×40)=0.621N/mm2?[τ]=1.782N/mm2

?????(mm)

q=5.28kN/m

νmax=0.093mm=200/400=0.5mm

4???????????

????????

R???max=2.971kN

????????

R'???max=2.119kN

??????:

?????(kN·m)

q=6.53kN/m

σ=Mmax/W=0.055×106/54000=1.012N/mm2=[f]=15.444N/mm2

?????(kN)

τmax=3 Vmax/(2bh)=3×1.162×1000/(2×90×40)=0.484N/mm2?[τ]=1.782N/mm2

?????(mm)

q=4.608kN/m

νmax=0.012mm=300/400=0.75mm

4???????????

????????

R???max=2.026kN

????????

R'???max=1.43kN

???2???,?????????????0.8?

??????:F=max[R???max,R???max]×0.8=Max[2.971,2.026]×0.8=2.377kN

??????:F'=max[R'???max,R'???max]×0.8=Max[2.119,1.43]×0.8=1.695kN

??????:

???????

??????(kN·m)

σ=Mmax/W=0.404×106/4120=98.172N/mm2=[f]=205N/mm2

??????(kN)

τmax=2Vmax/A=2×3.843×1000/384=20.018N/mm2?[τ]=125N/mm2

??????(mm)

??νmax=0.231mm?[ν]=600/400=1.5mm

???νmax=0.060mm?[ν]=2×100/400=0.5mm

4?????????

Rmax=7.409/0.8=9.261kN

???????????????????,????????N=0.95×9.261=8.798kN=Ntb=17.8kN

塔楼部分200×400梁板计算书

???????:

??????:

?????b=1000mm,??????:

W=bh2/6=1000×15×15/6=37500mm3,I=bh3/12=1000×15×15×15/12=281250mm4

q1=γ0×[1.3(G1k+(G2k+G3k)×h)+1.5×γL×Q1k]×b=1×[1.3×(0.1+(24+1.5)×0.4)+1.5×0.9×3]×1=17.44kN/m

q2=[1×(G1k+(G2k+G3k)×h)]×b=[1×(0.1+(24+1.5)×0.4)]×1=10.3kN/m

??????:

Mmax=0.125q1L2=0.125×17.44×0.22=0.087kN·m

σ=Mmax/W=0.087×106/37500=2.325N/mm2=[f]=15N/mm2

νmax=5q2L4/(384EI)=5×10.3×2004/(384×5400×281250)=0.141mm=[ν]=min[L/150,10]=min[200/150,10]=1.333mm

3???????

???(????????)

R1=R2=0.5q1L=0.5×17.44×0.2=1.744kN

???(????????)

R1'=R2'=0.5q2L=0.5×10.3×0.2=1.03kN

????????:

??????????????:q1?=R1/b=1.744/1=1.744kN/m

??????????????:q1?=R2/b=1.744/1=1.744kN/m

??????q?=q1?+q2+q3?+q4? =1.744+0.026+0.182+2.154=4.106kN/m

??????q?=q1?+q2+q3?+q4? =1.744+0.026+0.182+2.154=4.106kN/m

??????q=Max[q?,q?]=Max[4.106,4.106]=4.106kN/m

????????:

??????????????:q1?'=R1'/b=1.03/1=1.03kN/m

??????????????:q1?'=R2'/b=1.03/1=1.03kN/m

??????q?'=q1?'+q2'+q3?'+q4?'=1.03+0.02+0.14+0.878=2.068kN/m

??????q?'=q1?'+q2'+q3?'+q4?' =1.03+0.02+0.14+0.878=2.068kN/m

??????q'=Max[q?',q?']=Max[2.068,2.068]=2.068kN/m

?????,???????????????,???:

Mmax=max[0.125ql12,0.5ql22]=max[0.125×4.106×0.92,0.5×4.106×0.12]=0.416kN·m

σ=Mmax/W=0.416×106/54000=7.699N/mm2=[f]=15.444N/mm2

Vmax=max[0.625ql1,ql2]=max[0.625×4.106×0.9,4.106×0.1]=2.31kN

τmax=3Vmax/(2bh0)=3×2.31×1000/(2×40×90)=0.962N/mm2?[τ]=1.782N/mm2

ν1=0.521q'l14/(100EI)=0.521×2.068×9004/(100×9350×243×104)=0.311mm?[ν]=min[l1/150,10]=min[900/150,10]=6mm

ν2=q'l24/(8EI)=2.068×1004/(8×9350×243×104)=0.001mm?[ν]=min[2l2/150,10]=min[200/150,10]=1.333mm

4???????

????????

Rmax=max[1.25qL1,0.375qL1+qL2]=max[1.25×4.106×0.9,0.375×4.106×0.9+4.106×0.1]=4.619kN

?????????????????R1=4.619kN,R2=4.619kN

????????

Rmax'=max[1.25q'L1,0.375q'L1+q'L2]=max[1.25×2.068×0.9,0.375×2.068×0.9+2.068×0.1]=2.327kN

?????????????????R1'=2.327kN,R2'=2.327kN

????????,??2???,??????????=0.6,???????????Ks×Rn,Rn????????????

?????(kN·m)

σ=Mmax/W=0.141×106/4120=34.168N/mm2=[f]=205N/mm2

?????(kN)

Vmax=2.23kN

τmax=2Vmax/A=2×2.23×1000/384=11.616N/mm2?[τ]=125N/mm2

?????(mm)

νmax=0.01mm?[ν]=min[L/150,10]=min[300/150,10]=2mm

4???????

????????

???????R1=0.088kN,R2=0.63kN,R3=4.461kN,R4=0.63kN,R5=0.088kN

?????????????P1=0.088/0.6=0.146kN,P2=0.63/0.6=1.049kN,P3=4.461/0.6=7.434kN,P4=0.63/0.6=1.049kN,P5=0.088/0.6=0.146kN

1????????

????????N=max[R1,R5]=max[0.088,0.088]=0.088kN=0.85×8=6.8kN

????????40~65N·m??????????,????????!

2???????

????????N=max[P2,P3,P4]=7.434kN=[N]=30kN

hmax=max(ηh,h'+2ka)=max(1.2×1500,500+2×0.7×500)=1800mm

λ=hmax/i=1800/15.9=113.208?[λ]=150

???????!

???:φ=0.386

Mwd=γ0×γL×φwγQ×Mωk=γ0×γL×φwγQ×(ζ2×ωk×la×h2/10)=1×0.9×0.6×1.5×(1×0.028×0.9×1.52/10)=0.005kN·m

P1=0.146kN,P2=1.049kN,P3=7.434kN,P4=1.049kN,P5=0.146kN

???????????:

fd=Nd/(φA)+Mwd/W=7931.587/(0.386×424)+0.005×106/4490=49.576N/mm2=[f]=300N/mm2

H/B=2.95/11.1=0.266=3

?????????

????????????:qwk=l'a×ωfk=0.9×0.308=0.277kN/m:

??????????????????????????:

Fwk= l'a×Hm×ωmk=0.9×1×0.195=0.176kN

????????????????????????Mok:

Mok=0.5H2qwk+HFwk=0.5×2.952×0.277+2.95×0.176=1.724kN.m

B2l'a(gk1+ gk2)+2ΣGjkbj ?3γ0Mok

gk1——???????????????kN/m2

gk2——???????????????????????kN/m2

Gjk——??????????????????????kN

bj ——???????????????????????????m

B2l'a(gk1+ gk2)+2ΣGjkbj =B2l'a[qH/(l'a×l'b)+G1k]+2×Gjk×B/2=11.12×0.9×[0.15×2.95/(0.9×0.9)+0.5]+2×1×11.1/2=127.123kN.m=3γ0Mok =3×1×1.724=5.172kN.M

?????????????

F1=N=7.932kN

1?????????

DL／T 5562-2019标准下载 um =2[(a+h0)+(b+h0)]=1200mm

F=(0.7βhft+0.25σpc,m)ηumh0=(0.7×1×0.829+0.25×0)×1×1200×100/1000=69.636kN=F1=7.932kN

2??????????

??:fc=8.294N/mm2,βc=1,

闽2003G121：HRB400级钢筋框架节点构造详图.pdf βl=(Ab/Al)1/2=[(a+2b)×(b+2b)/(ab)]1/2=[(600)×(600)/(200×200)]1/2=3,Aln=ab=40000mm2

F=1.35βcβlfcAln=1.35×1×3×8.294×40000/1000=1343.628kN=F1=7.932kN